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250=20x+6x^2
We move all terms to the left:
250-(20x+6x^2)=0
We get rid of parentheses
-6x^2-20x+250=0
a = -6; b = -20; c = +250;
Δ = b2-4ac
Δ = -202-4·(-6)·250
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-80}{2*-6}=\frac{-60}{-12} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+80}{2*-6}=\frac{100}{-12} =-8+1/3 $
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